Stat 226 - Lecture 10
02/13/14
Your Turn
- Suppose \( X \sim N(12, 2^2) \). Find the value of \( x^* \) for each of the following scenarios:
- \( P(X < x^*) = 0.33 \) (\( x^* \) is called the 33rd percentile)
- \( P(X < x^*) = 0.66 \) (\( x^* \) is called the 66th percentile)
- \( P(X < x^*) = 0.01 \) (\( x^* \) is called the 1st percentile)
- Suppose monthly revenue in your business market is known to vary according to a normal distribution with mean of $500 thousand and variance of $200 thousand.
- How much revenue do you need next month in order to sell more than 98% of the entire market?
- What monthly revenue figure would imply that 40% of the market receieved a higher revenue?
Translating Random Variables
- By now, we are familiar with translating \( X \sim N(\mu, \sigma^2) \) to \( Z \sim N(0,1) \).
- We do this by shifting \( X \) by \( \mu \) and scaling by \( 1/\sigma \) (ie, \( Z = \frac{X-\mu}{\sigma} \))
- As it turns out, shifting a normal random variable will always give us another normal random variable!
- For instance, suppose \( Y = X - \mu \). Then \( Y \sim \)
\( N(0, \sigma^2) \)
- This is a useful idea if we know the distribution of \( X \), but are asked a question about \( Y \).
An example
- It is a well known that \( Revenue - Cost \) =
\( Profit! \)
- Suppose you are a used-car dealership owner. You have the opportunity to buy a car for $1000.
- You don't know how much it will sell for, but revenue generated from similar cars can be described by \( X \sim N(1200, 175^2) \).
- What is the probability that you will profit off the car?
- That is, what is the probability that revenue exceeds cost?
- Let \( Y \) be profit. Then \( Y = \)
\( X - 1000 \).
- Therefore, \( Y \sim N( \)
\( 200, 175^2) \)
- So, the probability of profit is \( P(Y > 0) \)!
Disclaimer
- Everything we've done in Chapter 12 requires that we know a population is normally distributed.
- Of course, we never actually know this, but we can use a sample to assess whether the normal assumption is reasonable or not.
- The demonstrate how we make this assessment, we will study some baseball data :)
Histogram of hits per game in baseball
- In a baseball game, both teams have several attempts to hit the baseball in play.
- I collected data on total # of hits by home and away teams in 2011.
- This histogram shows the distribution of hits per game.
- Pretty close to a symmetric, bell-shaped distribution. Let's fit a normal distribution to it!
Fitting a normal distribution to data
- We can fit a normal distribution to this data by:
- setting the mean parameter \( \mu \) equal to the sample mean \( \bar{x} \) = 8.9
- setting the variance parameter \( \sigma^2 \) equal to the sample variance \( s^2 \) = 12.2
Inference with empirical rule
- Think about selecting one game at random. Before selecting, we can make inference using a statistical model for the population of games: \( X \sim N(\mu = 8.9, \sigma^2 = 12.2) \)
- Note that \( \sigma = \sqrt{12.2} = 3.5 \)
- If we were to pick one game at random, there is a 68% chance of observing between (8.9 - 3.5, 8.9 + 3.5)
=> (5.4, 12.4)
hits in that game.
Is runs per game really normally distributed??
- If runs/game was perfectly normal, the points would fall exactly on the red line.
- Since nothing is perfectly normal, we expect some deviation from this line.
- The real question is whether this deviation is statistically significant.
- Suppose the deviation here is significant. What does that imply?
- See last 3 slides in lecture notes for more examples.